Some Pattern's in c

Write a C program to print the following pattern:

      *
    * * *
  * * * * *
* * * * * * *
*           *
* *       * *
* * *   * * *
* * * * * * *
* * *   * * *
* *       * *
*           *
* * * * * * *
  * * * * *
    * * *
      *

Program:

#include 
/*
 * nos = Num. of spaces required in the triangle.
 * i   = Counter for the num. of charcters to print in each row
 * skip= A flag for checking whether to
 *       skip a character in a row.
 *
 */
int triangle(int nos, int i, int skip) {
 char prnt = '*';
 int s, j;
 for (s = nos; s >= 1; s--) {
  printf("  ");
 }
 for (j = 1; j <= i; j++) {
  if (skip != 0) {
   if (i == 4 && j == 1) {
    continue;
   }
  }
  printf("%2c", prnt);
 }
 return 0;
}

int main() {
 int i, nos = 4;
 for (i = 1; i <= 7; (i = i + 2)) {
  triangle(nos, i, 0);
  nos--;
  printf("\n");
 }
 nos = 5;
 for (i = 1; i <= 4; i++) {
triangle(1, i, 0); //one space needed in each case of the formation
triangle(nos, i, 1); //skip printing one star in the last row.
nos = nos - 2;
printf("\n");
}
nos = 1;
for (i = 3; i >= 1; i--) {
  triangle(1, i, 0);
  triangle(nos, i, 0);
  nos = nos + 2;
  printf("\n");
 }
 nos = 1;
 for (i = 7; i >= 1; (i = i - 2)) {
  triangle(nos, i, 0);
  nos++;
  printf("\n");
 }
 return 0;
}

Some Pattern's in C

1). Write a C program to print the following pattern:

         *
      *  *
   *  *  *
*  *  *  *

Program:

/* This is a simple mirror-image of a right angle triangle */

#include 
int main() {
 char prnt = '*';
 int i, j, nos = 4, s;
 for (i = 1; i <= 5; i++) {
for (s = nos; s >= 1; s--) {  // Spacing factor
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  printf("\n");
  --nos;   // Controls the spacing factor
 }
 return 0;
}

Write C program to print the following pattern:

*                   *
* * *           * * *
* * * * *   * * * * *
* * * * * * * * * * *

Program:

#include
int main() {
 char prnt = '*';
 int i, j, k, s, c = 1, nos = 9;
 for (i = 1; c <= 4; i++) {
     // As we want to print the columns in odd sequence viz. 1,3,5,.etc
  if ((i % 2) != 0) {
   for (j = 1; j <= i; j++) {
 printf("%2c", prnt);
}
for (s = nos; s >= 1; s--) { //The spacing factor
    if (c == 4 && s == 1) {
     break;
    }
    printf("  ");
   }
   for (k = 1; k <= i; k++) {
    if (c == 4 && k == 5) {
     break;
    }
    printf("%2c", prnt);
   }
   printf("\n");
   nos = nos - 4;  // controls the spacing factor
   ++c;
  }
 }
 return 0;
}

Write C program to print the following pattern:

*                         *
   *                   *
*     *             *     *
   *     *       *     *
*     *      *      *     *
   *     *       *     *
*     *             *     *
   *                   *
*                         *

Program:

#include
int main() {
 char prnt = '*';
 int i, j, k, s, p, r, nos = 7;

 for (i = 1; i <= 5; i++) {
  for (j = 1; j <= i; j++) {
 if ((i % 2) != 0 && (j % 2) != 0) {
printf("%3c", prnt);
}
else if ((i % 2) == 0 && (j % 2) == 0) {
printf("%3c", prnt);
}
else {
printf("   ");
}
}
for (s = nos; s >= 1; s--) {  // for the spacing factor
   printf("   ");
  }
  for (k = 1; k <= i; k++) { //Joining seperate figures
if (i == 5 && k == 1) {
 continue;
}
if ((k % 2) != 0) {
printf("%3c", prnt);
}
else {
printf("   ");
}
}
printf("\n");
nos = nos - 2;   // space control
}  

nos = 1; // remaining half..

for (p = 4; p >= 1; p--)

{

for (r = 1; r <= p; r++)

{

if ((p % 2) != 0 && (r % 2) != 0)

{

printf("%3c", prnt);

}

else if ((p % 2) == 0 && (r % 2) == 0)

{

printf("%3c", prnt);

}

else

{

printf(" ");

}

}

for (s = nos; s >= 1; s--)

{

printf(" ");

} 

 for (k = 1; k <= p; k++)

{  

if ((k % 2) != 0)

 {

printf("%3c", prnt);

}

else

 {   

 printf(" ");

}

} 

 nos = nos + 2; // space control

printf("\n");

}

return 0;

}

print pattern's

#include<stdio.h>

int main() {

      int i = 1, j = 5;

      printf("----------\n");

      printf("a \t b \n");

      printf("----------\n");

      /* logic: while loop repeats

       * 5 times i.e. until

       * the condition i<=5 fails */

      while (i <= 5) {

            /* i and j value printed */

            printf("%d \t %d\n", i, j);

            /* i and j value incremented

             by 1 for every iteration */

            i++;

            j--;

      }

      printf("----------");

      return 0;

}

 

 

 

OUTPUT:--

 

------
  a b
 ------
  1 5
  2 4
  3 3
  4 2
  5 1
 ------

vb script for sample

<html>
<body>
<script type ="text/vbscript">
dim a,b,x(2,2),i,j
x(0,0)="Volvo"
x(0,1)="BMW"
x(0,2)="Ford"
x(1,0)="HONDA"
x(1,1)="Mercedz"
x(1,2)="Bonaza"
x(2,0)="volks"
x(2,1)="walsfoken"
x(2,2)="sex"
a=inputbox("enter your name.=")
b=prompt("enter password:=")
msgbox a
If b=10000 Then
 alert("you are authorized to see the name of cars")

 document.write("<h2>hi you are NITESH!! WelcomeYOU</h2>")
 document.write("<h3>welcome...!you are Authorised person..:</h3>")
for i=0 to 2
   
    for j=0 to 2
        document.write(x(i,j) & "<br />")
    next
next

else
 alert("you are not authorized to see the name of cars")

 document.write("<h1>hi you are not authorized..!!</h1>")
 document.write("<h3>welcome...!you are fAKE person..:</h3>")
End If


</script>

</body>

</html>

niteshnagar.blogspot.com

Adding range checking for user input

#include

using namespace std;

int main()

{

cout << "Temperature Conversion Program." << endl;

cout << "Enter degrees Celsius from 0 to 100: " << flush;

double degreesCelsius;

cin >> degreesCelsius;

if((degreesCelsius < 0) || (degreesCelsius > 100)){

cout << "The number you entered is invalid." << endl;

}else{

double degreesFahrenheit = degreesCelsius*(9.0/5.0)+32;

cout << degreesCelsius << " degrees Celsius = ";

cout << degreesFahrenheit << " degrees Fahrenheit" << endl;

}

}

To generate more random numbers we simply call rand() repeatedly:

#include

#include

using namespace std;

int main()

{

int random_integer;

for(int index=0; index<10; index++){

random_integer = rand();

cout << random_integer << endl;

}

}